47x^2+23x=0

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Solution for 47x^2+23x=0 equation:



47x^2+23x=0
a = 47; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·47·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*47}=\frac{-46}{94} =-23/47 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*47}=\frac{0}{94} =0 $

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